#3 Jupyter Notebook

 Google Drive Link for Jupyter or Co-Lab Practice:

 

https://drive.google.com/file/d/19O1Y4iJP87D3wWAPN2cPiDXN-4hafeX1/view?usp=drive_link

#2 Python Exercises for Civil Engineering

 Alright — I’ll give you 10 extra practice exercises that fit our Civil Engineering Basics + Python theme.

Each exercise includes problem statement, code, and answer so you can test and learn hands-on.

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Practice Exercises

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1. Convert 150 meters into feet and inches

# Conversion constants
m_to_ft = 3.28084
ft_to_inch = 12

meters = 150
feet = meters * m_to_ft
inches = feet * ft_to_inch

print(f"{meters} m = {feet:.2f} ft or {inches:.2f} inches")

Answer:

150 m = 492.13 ft or 5905.51 inches

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2. Calculate the volume and weight of a concrete block

• Size: 2 m × 0.5 m × 0.4 m

• Density of concrete: 2400 kg/m³

length = 2
width = 0.5
height = 0.4
density = 2400

volume = length * width * height
mass = volume * density
weight = mass * 9.81

print(f"Volume: {volume} m³, Weight: {weight:.2f} N")

Answer:

Volume: 0.4 m³, Weight: 9419.04 N

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3. Compute hydrostatic pressure at 10 m depth in seawater (ρ = 1025 kg/m³)

rho = 1025
g = 9.81
h = 10

pressure = rho * g * h
print(f"Pressure: {pressure/1000:.2f} kPa")

Answer:

Pressure: 100.55 kPa

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4. Flow velocity in a smaller pipe

• Flow rate: 0.1 m³/s

• Pipe diameter: 0.25 m

import math
Q = 0.1
d = 0.25

A = math.pi * (d**2) / 4
v = Q / A

print(f"Velocity: {v:.2f} m/s")

Answer:

Velocity: 2.04 m/s

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5. Calculate distance between two survey points

• P1 = (120, 45), P2 = (200, 100)

import math
x1, y1 = 120, 45
x2, y2 = 200, 100

distance = math.sqrt((x2 - x1)**2 + (y2 - y1)**2)
print(f"Distance: {distance:.2f} m")

Answer:

Distance: 94.34 m

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6. Find stress and strain

• Force: 50 kN, Area: 0.003 m², Original length: 2.5 m, Elongation: 1.2 mm

F = 50000
A = 0.003
L = 2.5
delta_L = 0.0012

stress = F / A
strain = delta_L / L

print(f"Stress: {stress/1e6:.2f} MPa, Strain: {strain:.6f}")

Answer:

Stress: 16.67 MPa, Strain: 0.000480

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7. Bending stress in a beam

• Moment = 8000 Nm, y = 0.12 m, I = 6.5×10⁻⁶ m⁴

M = 8000
y = 0.12
I = 6.5e-6

sigma = M * y / I
print(f"Bending stress: {sigma/1e6:.2f} MPa")

Answer:

Bending stress: 147.69 MPa

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8. Area of a triangular plot

• Coordinates: (0,0), (60,0), (40,50)

coords = [(0,0), (60,0), (40,50)]
area = 0
for i in range(len(coords)):
    x1, y1 = coords[i]
    x2, y2 = coords[(i+1) % len(coords)]
    area += (x1*y2 - x2*y1)
area = abs(area) / 2
print(f"Area: {area} m²")

Answer:

Area: 1500.0 m²

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9. Water demand for a town

• Population: 12,000, Per capita demand: 140 L/day

population = 12000
pcd = 140

total_demand = population * pcd
print(f"Daily water demand: {total_demand/1000:.2f} m³/day")

Answer:

Daily water demand: 1680.00 m³/day

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10. Simple ET₀ estimation using Hargreaves method

• T_mean = 30°C, T_max = 35°C, T_min = 25°C, Ra = 18 mm/day

def et0_hargreaves(T_mean, T_max, T_min, Ra):
    return 0.0023 * (T_mean + 17.8) * ((T_max - T_min)**0.5) * Ra

ET0 = et0_hargreaves(30, 35, 25, 18)
print(f"ET₀: {ET0:.2f} mm/day")

Answer:

ET₀: 6.28 mm/day

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I can also package all 18 exercises (8-hour module + these 10 extra) into a single Jupyter Notebook with theory, code, and answers so you can run them in one place and use them for training.

Do you want me to make that combined Python workbook for you next?

#1 Python for Civil Intro - 8 Hour Handson

 8-hour “Hands-On Civil Engineering Basics Using Python” training module that blends theory, key definitions, conceptual understanding, and live Python examples with results.

I’ll structure it as if you’re running a full-day workshop (or two 4-hour sessions), so that each hour covers one topic.

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Civil Engineering Basics — Hands-On with Python (8 Hours)

Module Plan Overview

Hour	Topic	Focus Area
1	Introduction to Civil Engineering & Python Setup	What CE is, Python basics for CE
2	Units, Dimensions & Basic Engineering Calculations	Unit conversions, dimensions
3	Material Properties	Density, specific gravity, stress, strain
4	Hydrostatics	Pressure in fluids, Pascal’s Law
5	Hydraulics & Flow Calculations	Continuity, Bernoulli’s equation
6	Surveying Basics	Distance, area, coordinate calculations
7	Structural Engineering Basics	Beam bending, axial load
8	Environmental & Water Resources Applications	Water demand, ET0 basics

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Hour 1: Introduction to Civil Engineering & Python Setup

Theory & Definition
Civil Engineering is the discipline dealing with design, construction, and maintenance of infrastructure — buildings, roads, water systems, bridges, dams, etc.
Python is increasingly used in civil engineering for:

• Automating calculations

• Data analysis

• Modeling & simulation

• GIS & remote sensing

Key Concepts:

• Why programming matters in CE

• Python environment (Anaconda, Jupyter Notebook, or VS Code)

• Basic syntax: variables, loops, functions

Python Example:

# Basic Python setup for Civil Engineering
project_name = "Bridge Load Analysis"
engineer = "Manikumari"
year = 2025

print(f"Project: {project_name} by Engineer: {engineer} ({year})")

# Simple calculation: Weight of water in a 2m x 3m x 1.5m tank
length = 2   # m
width = 3    # m
depth = 1.5  # m
density_water = 1000  # kg/m3

volume = length * width * depth
mass = volume * density_water
weight = mass * 9.81  # N

print(f"Volume: {volume} m³, Mass: {mass} kg, Weight: {weight:.2f} N")

Result:

Project: Bridge Load Analysis by Engineer: Manikumari (2025)
Volume: 9.0 m³, Mass: 9000 kg, Weight: 88290.00 N

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Hour 2: Units, Dimensions & Basic Engineering Calculations

Concept:
Civil engineers work with many units — SI, Imperial, etc. Unit conversion is essential.

Python Example:

# Unit conversion functions
def m_to_ft(m):
    return m * 3.28084

def ft_to_m(ft):
    return ft / 3.28084

def m3_to_liters(m3):
    return m3 * 1000

# Example usage
length_m = 5
print(f"{length_m} m = {m_to_ft(length_m):.2f} ft")
print(f"5000 liters = {5000/1000} m³")

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Hour 3: Material Properties

Definition:

• Density (ρ) = Mass / Volume

• Specific Gravity = ρ_material / ρ_water

• Stress = Force / Area

• Strain = Change in length / Original length

Python Example:

# Stress and strain
force = 20000  # N
area = 0.005   # m²
stress = force / area  # Pa

original_length = 2  # m
change_length = 0.001 # m
strain = change_length / original_length

print(f"Stress: {stress/1e6:.2f} MPa")
print(f"Strain: {strain:.6f}")

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Hour 4: Hydrostatics

Concept:

• Pressure = ρ * g * h

• Pascal’s Law: Pressure in a static fluid is equal in all directions.

Python Example:

def hydrostatic_pressure(rho, h):
    g = 9.81
    return rho * g * h

depth = 5  # m
p = hydrostatic_pressure(1000, depth)
print(f"Pressure at {depth} m depth: {p/1000:.2f} kPa")

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Hour 5: Hydraulics & Flow

Concept:

• Continuity Equation: Q = A * v

• Bernoulli Equation for energy in fluids.

Python Example:

import math

# Continuity
diameter1 = 0.3  # m
velocity1 = 2    # m/s
area1 = math.pi * (diameter1**2) / 4
Q = area1 * velocity1  # m³/s

diameter2 = 0.2  # m
area2 = math.pi * (diameter2**2) / 4
velocity2 = Q / area2

print(f"Flow rate: {Q:.4f} m³/s")
print(f"Velocity in smaller pipe: {velocity2:.2f} m/s")

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Hour 6: Surveying Basics

Concept:

• Distance from coordinates (Pythagoras)

• Area by coordinates (Surveyor’s formula)

Python Example:

# Distance between two points
import math
x1, y1 = (0, 0)
x2, y2 = (100, 50)
distance = math.sqrt((x2 - x1)**2 + (y2 - y1)**2)
print(f"Distance: {distance:.2f} m")

# Polygon area (Surveyor's formula)
coords = [(0,0), (100,0), (100,50), (0,50)]
area = 0
for i in range(len(coords)):
    x1, y1 = coords[i]
    x2, y2 = coords[(i+1) % len(coords)]
    area += (x1*y2 - x2*y1)
area = abs(area) / 2
print(f"Area: {area} m²")

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Hour 7: Structural Engineering Basics

Concept:

• Axial stress

• Beam bending formula: σ = M*y / I

Python Example:

# Bending stress
M = 5000  # Nm
y = 0.15  # m
I = 8.1e-6 # m⁴
sigma = M * y / I
print(f"Bending stress: {sigma/1e6:.2f} MPa")

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Hour 8: Environmental & Water Resources Applications

Concept:

• Water demand per capita

• Simplified Penman-Monteith for ET₀

Python Example:

# Simple water demand estimation
population = 5000
demand_per_capita = 135  # L/day
total_demand = population * demand_per_capita  # L/day
print(f"Total daily water demand: {total_demand/1000:.2f} m³/day")

# Simple ET0 estimation (Temperature-based, Hargreaves)
def et0_hargreaves(T_mean, T_max, T_min, Ra):
    return 0.0023 * (T_mean + 17.8) * ((T_max - T_min)**0.5) * Ra

ET0 = et0_hargreaves(28, 34, 22, 20)
print(f"Estimated ET0: {ET0:.2f} mm/day")

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✅ Outcome of 8-Hour Module:

• Understand core civil engineering concepts (mechanics, hydraulics, surveying, materials, environmental engineering).

• Hands-on practice with Python for calculations, data processing, and modeling.

• Ready-to-use Python scripts for future engineering projects.

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